solvefor p,3p^2+9p=-6

解

p, 3 p^{2} + 9 p = - 6

p = - 1, p = - 2

解答ステップ

3 p^{2} + 9 p = - 6

6

を左側に移動します

3 p^{2} + 9 p + 6 = 0

解くとthe二次式

p_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

9^{2} - 4 \cdot 3 \cdot 6 = 3

p_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 3}

解を分離する

p_{1} = \frac{- 9 + 3}{2 \cdot 3}, p_{2} = \frac{- 9 - 3}{2 \cdot 3}

p = \frac{- 9 + 3}{2 \cdot 3} : - 1

p = \frac{- 9 - 3}{2 \cdot 3} : - 2

二次equationの解:

p = - 1, p = - 2