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受欢迎的代数 >

(x-3)(4+3)-x^2-5/4 =(x-x/5)-(3x-3/4)

解答

(x - 3) (4 + 3) - x^{2} - \frac{5}{4} = (x - \frac{x}{5}) - (3 x - \frac{3}{4})

解答

x = \frac{23}{5} - i \frac{46}{5}, x = \frac{23}{5} + i \frac{46}{5}

求解步骤

(x - 3) (4 + 3) - x^{2} - \frac{5}{4} = (x - \frac{x}{5}) - (3 x - \frac{3}{4})

在两边乘以

4

28 (x - 3) - 4 x^{2} - 5 = 4 (x - \frac{x}{5}) - 4 (3 x - \frac{3}{4})

展开

28 (x - 3) - 4 x^{2} - 5 : - 4 x^{2} + 28 x - 89

展开

4 (x - \frac{x}{5}) - 4 (3 x - \frac{3}{4}) : - \frac{44 x}{5} + 3

- 4 x^{2} + 28 x - 89 = - \frac{44 x}{5} + 3

将

3

para o lado esquerdo

- 4 x^{2} + 28 x - 92 = - \frac{44 x}{5}

将

\frac{44 x}{5}

para o lado esquerdo

\frac{- 20 x ^{2} + 184 x}{5} - 92 = 0

改写成标准形式

a x^{2} + b x + c = 0

- 4 x^{2} + \frac{184 x}{5} - 92 = 0

使用求根公式求解

x_{1, 2} = \frac{- \frac{184}{5} \pm ( \frac{184}{5} ) ^{2} - 4 ( - 4 ) ( - 92 )}{2 ( - 4 )}

化简

(\frac{184}{5})^{2} - 4 (- 4) (- 92) : i \frac{8 46}{5}

x_{1, 2} = \frac{- \frac{184}{5} \pm i \frac{8 46}{5}}{2 ( - 4 )}

将解分隔开

x_{1} = \frac{- \frac{184}{5} + i \frac{8 46}{5}}{2 ( - 4 )}, x_{2} = \frac{- \frac{184}{5} - i \frac{8 46}{5}}{2 ( - 4 )}

x = \frac{- \frac{184}{5} + i \frac{8 46}{5}}{2 ( - 4 )} : \frac{23}{5} - i \frac{46}{5}

x = \frac{- \frac{184}{5} - i \frac{8 46}{5}}{2 ( - 4 )} : \frac{23}{5} + i \frac{46}{5}

二次方程组的解是:

x = \frac{23}{5} - i \frac{46}{5}, x = \frac{23}{5} + i \frac{46}{5}

作图

流行的例子

x^{2} + \frac{3}{2} x + 1 = 0

completesquare 3x^2-6x+4

co m pl e t es q u a re 3 x^{2} - 6 x + 4

- 3 x^{2} + 30 x - 75 = 0

x^{2} = 4 x - 15

solvefor x,x^2+m^2x(m-2)=2m^5

so l v e f or x, x^{2} + m^{2} x (m - 2) = 2 m^{5}