solvefor x,x^2-4x+2=0

解

x, x^{2} - 4 x + 2 = 0

x = 2 + 2, x = 2 - 2

十進法表記

x = 3.41421 \dots, x = 0.58578 \dots

解答ステップ

x^{2} - 4 x + 2 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 2 = 22

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - 4 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 2}{2 \cdot 1} : 2 + 2

x = \frac{- ( - 4 ) - 2 2}{2 \cdot 1} : 2 - 2

二次equationの解:

x = 2 + 2, x = 2 - 2