-180t^2+30t+14=0

解

- 180 t^{2} + 30 t + 14 = 0

t = - \frac{- 5 + 305}{60}, t = \frac{5 + 305}{60}

十進法表記

t = - 0.20773 \dots, t = 0.37440 \dots

解答ステップ

- 180 t^{2} + 30 t + 14 = 0

解くとthe二次式

t_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 ( - 180 ) \cdot 14}{2 ( - 180 )}

3 0^{2} - 4 (- 180) \cdot 14 = 6305

t_{1, 2} = \frac{- 30 \pm 6 305}{2 ( - 180 )}

解を分離する

t_{1} = \frac{- 30 + 6 305}{2 ( - 180 )}, t_{2} = \frac{- 30 - 6 305}{2 ( - 180 )}

t = \frac{- 30 + 6 305}{2 ( - 180 )} : - \frac{- 5 + 305}{60}

t = \frac{- 30 - 6 305}{2 ( - 180 )} : \frac{5 + 305}{60}

二次equationの解:

t = - \frac{- 5 + 305}{60}, t = \frac{5 + 305}{60}