(2x+1)(x+3)-x(x-2)=0

Lösung

(2 x + 1) \cdot (x + 3) - x \cdot (x - 2) = 0

x = \frac{- 9 + 69}{2}, x = \frac{- 9 - 69}{2}

Dezimale

x = - 0.34668 \dots, x = - 8.65331 \dots

Schritte zur Lösung

(2 x + 1) (x + 3) - x (x - 2) = 0

Schreibe

(2 x + 1) (x + 3) - x (x - 2)

um:

x^{2} + 9 x + 3

x^{2} + 9 x + 3 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 3 = 69

x_{1, 2} = \frac{- 9 \pm 69}{2 \cdot 1}

Trenne die Lösungen

x_{1} = \frac{- 9 + 69}{2 \cdot 1}, x_{2} = \frac{- 9 - 69}{2 \cdot 1}

x = \frac{- 9 + 69}{2 \cdot 1} : \frac{- 9 + 69}{2}

x = \frac{- 9 - 69}{2 \cdot 1} : \frac{- 9 - 69}{2}

Die Lösungen für die quadratische Gleichung sind:

x = \frac{- 9 + 69}{2}, x = \frac{- 9 - 69}{2}

x^{2} + 10 x + 12 = 2 x + 52 x + 5

22 - [3 x - (2 x - 1)] = 5 x + {6 - [2 x - 7] (x - 1)}

- 27 x + 32 x^{2} - 39 = 0

(\frac{1}{2} x + 3)^{2} - x (2 x - 1) = - 1

(x + 1)^{2} + (2 x + 4)^{2} = (3 x + 1)^{2}