y^2-40y=0

解

y^{2} - 40 y = 0

y = 40, y = 0

解答ステップ

y^{2} - 40 y = 0

解くとthe二次式

y_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 40)^{2} - 4 \cdot 1 \cdot 0 = 40

y_{1, 2} = \frac{- ( - 40 ) \pm 40}{2 \cdot 1}

解を分離する

y_{1} = \frac{- ( - 40 ) + 40}{2 \cdot 1}, y_{2} = \frac{- ( - 40 ) - 40}{2 \cdot 1}

y = \frac{- ( - 40 ) + 40}{2 \cdot 1} : 40

y = \frac{- ( - 40 ) - 40}{2 \cdot 1} : 0

二次equationの解:

y = 40, y = 0