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受欢迎的代数 >

solvefor a,a^2-2ab+b^2+c^2=0

解答

求解

a, a^{2} - 2 ab + b^{2} + c^{2} = 0

解答

a = b + i c, a = b - i c

求解步骤

a^{2} - 2 ab + b^{2} + c^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

a^{2} - 2 ba + b^{2} + c^{2} = 0

使用求根公式求解

a_{1, 2} = \frac{- ( - 2 b ) \pm ( - 2 b ) ^{2} - 4 \cdot 1 \cdot ( b ^{2} + c ^{2} )}{2 \cdot 1}

化简

(- 2 b)^{2} - 4 \cdot 1 \cdot (b^{2} + c^{2}) : 2 i c

a_{1, 2} = \frac{- ( - 2 b ) \pm 2 i c}{2 \cdot 1}

将解分隔开

a_{1} = \frac{- ( - 2 b ) + 2 i c}{2 \cdot 1}, a_{2} = \frac{- ( - 2 b ) - 2 i c}{2 \cdot 1}

a = \frac{- ( - 2 b ) + 2 i c}{2 \cdot 1} : b + i c

a = \frac{- ( - 2 b ) - 2 i c}{2 \cdot 1} : b - i c

二次方程组的解是:

a = b + i c, a = b - i c

作图

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