What are the solutions to the equation r^2=(-5)^2+12^2 ?

The solutions to the equation r^2=(-5)^2+12^2 are r=13,r=-13

Find the zeros of r^2=(-5)^2+12^2

The zeros of r^2=(-5)^2+12^2 are r=13,r=-13

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r^{2} = (- 5)^{2} + 1 2^{2}

r = 13, r = - 13

Solution steps

r^{2} = (- 5)^{2} + 1 2^{2}

Simplify

(- 5)^{2} + 1 2^{2} : 169

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 169, r = - 169

169 = 13

- 169 = - 13

r = 13, r = - 13

k^{2} + 44 k = 0

9 q^{2} - 11 q + 2 = 3 q^{2}

7 x^{2} - 9 x + 3 = 0

(x + 2)^{2} + 3 = 0

x^{2} + 8 x = - 24

What are the solutions to the equation r^2=(-5)^2+12^2 ?
The solutions to the equation r^2=(-5)^2+12^2 are r=13,r=-13
Find the zeros of r^2=(-5)^2+12^2
The zeros of r^2=(-5)^2+12^2 are r=13,r=-13