What are the solutions to the equation x^2+11x=-35 ?

The solutions to the equation x^2+11x=-35 are x=-11/2+i(sqrt(19))/2 ,x=-11/2-i(sqrt(19))/2

Find the zeros of x^2+11x=-35

The zeros of x^2+11x=-35 are x=-11/2+i(sqrt(19))/2 ,x=-11/2-i(sqrt(19))/2

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x^{2} + 11 x = - 35

x = - \frac{11}{2} + i \frac{19}{2}, x = - \frac{11}{2} - i \frac{19}{2}

Solution steps

x^{2} + 11 x = - 35

Move

35

to the left side

x^{2} + 11 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

Simplify

1 1^{2} - 4 \cdot 1 \cdot 35 : 19 i

x_{1, 2} = \frac{- 11 \pm 19 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 19 i}{2 \cdot 1}, x_{2} = \frac{- 11 - 19 i}{2 \cdot 1}

x = \frac{- 11 + 19 i}{2 \cdot 1} : - \frac{11}{2} + i \frac{19}{2}

x = \frac{- 11 - 19 i}{2 \cdot 1} : - \frac{11}{2} - i \frac{19}{2}

The solutions to the quadratic equation are:

x = - \frac{11}{2} + i \frac{19}{2}, x = - \frac{11}{2} - i \frac{19}{2}

y = 0.00249 (1 - \frac{1.197 - 1100 y}{- 2})^{2}

(h - 4) (h - 10) = 0

m^{2} + 7 m - 8 = 0

0 = - 16 t^{2} + 85 t + 30

h^{2} - 16 h - 17 = 0

What are the solutions to the equation x^2+11x=-35 ?
The solutions to the equation x^2+11x=-35 are x=-11/2+i(sqrt(19))/2 ,x=-11/2-i(sqrt(19))/2
Find the zeros of x^2+11x=-35
The zeros of x^2+11x=-35 are x=-11/2+i(sqrt(19))/2 ,x=-11/2-i(sqrt(19))/2