3Q^2-192Q+3500=0

解

3 Q^{2} - 192 Q + 3500 = 0

Q = 32 + i \frac{2 321}{3}, Q = 32 - i \frac{2 321}{3}

解答ステップ

3 Q^{2} - 192 Q + 3500 = 0

解くとthe二次式

Q_{1, 2} = \frac{- ( - 192 ) \pm ( - 192 ) ^{2} - 4 \cdot 3 \cdot 3500}{2 \cdot 3}

簡素化

(- 192)^{2} - 4 \cdot 3 \cdot 3500 : 4321 i

Q_{1, 2} = \frac{- ( - 192 ) \pm 4 321 i}{2 \cdot 3}

解を分離する

Q_{1} = \frac{- ( - 192 ) + 4 321 i}{2 \cdot 3}, Q_{2} = \frac{- ( - 192 ) - 4 321 i}{2 \cdot 3}

Q = \frac{- ( - 192 ) + 4 321 i}{2 \cdot 3} : 32 + i \frac{2 321}{3}

Q = \frac{- ( - 192 ) - 4 321 i}{2 \cdot 3} : 32 - i \frac{2 321}{3}

二次equationの解:

Q = 32 + i \frac{2 321}{3}, Q = 32 - i \frac{2 321}{3}