x^2+sqrt(3)x-6=0

解

x^{2} + 3 x - 6 = 0

x = 3, x = - 23

十進法表記

x = 1.73205 \dots, x = - 3.46410 \dots

解答ステップ

x^{2} + 3 x - 6 = 0

解くとthe二次式

x_{1, 2} = \frac{- 3 \pm ( 3 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(3)^{2} - 4 \cdot 1 \cdot (- 6) = 33

x_{1, 2} = \frac{- 3 \pm 3 3}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 3 + 3 3}{2 \cdot 1}, x_{2} = \frac{- 3 - 3 3}{2 \cdot 1}

x = \frac{- 3 + 3 3}{2 \cdot 1} : 3

x = \frac{- 3 - 3 3}{2 \cdot 1} : - 23

二次equationの解:

x = 3, x = - 23