簡約 (abc^2+b^2c^3+a^2b^7c^5)/(abc)

解

簡約

\frac{ab c ^{2} + b ^{2} c ^{3} + a ^{2} b ^{7} c ^{5}}{ab c}

\frac{c ( a + b c + a ^{2} b ^{6} c ^{3} )}{a}

解答ステップ

\frac{ab c ^{2} + b ^{2} c ^{3} + a ^{2} b ^{7} c ^{5}}{ab c}

共通項をくくり出す

b c^{2} : b c^{2} (a + b c + a^{2} b^{6} c^{3})

= \frac{b c ^{2} ( a + b c + a ^{2} b ^{6} c ^{3} )}{ab c}

共通因数を約分する:

b

= \frac{c ^{2} ( a + b c + a ^{2} b ^{6} c ^{3} )}{a c}

指数の規則を適用する:

a^{b + c} = a^{b} \cdot a^{c}

c^{2} = cc

= \frac{cc ( a + b c + a ^{2} b ^{6} c ^{3} )}{a c}

共通因数を約分する:

c

= \frac{c ( a + b c + a ^{2} b ^{6} c ^{3} )}{a}