What is (9-2i)+(4+7i)-(3-5i) ?

The solution to (9-2i)+(4+7i)-(3-5i) is 10+10i

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simplify (9-2i)+(4+7i)-(3-5i)

simplify

(9 - 2 i) + (4 + 7 i) - (3 - 5 i)

10 + 10 i

Solution steps

(9 - 2 i) + (4 + 7 i) - (3 - 5 i)

Simplify

(9 - 2 i) + (4 + 7 i) - (3 - 5 i) : 9 - 2 i + 4 + 7 i - (3 - 5 i)

= 9 - 2 i + 4 + 7 i - (3 - 5 i)

Group like terms

= - 2 i + 7 i - (3 - 5 i) + 9 + 4

Add similar elements:

- 2 i + 7 i = 5 i

= 5 i - (3 - 5 i) + 9 + 4

Add the numbers:

9 + 4 = 13

= 5 i - (3 - 5 i) + 13

Remove parentheses:

- (a + bi) = - a - bi

= 5 i + - 3 - (- 5) i + 13

Group like terms

= 5 i - (- 5) i - 3 + 13

Add similar elements:

5 i - (- 5) i = 10 i

= 10 i - 3 + 13

Add the numbers:

- 3 + 13 = 10

= 10 i + 10

Rewrite in standard complex form:

10 + 10 i

= 10 + 10 i

\frac{1}{6} - \frac{1}{6}

\frac{3 \cdot 1 0 ^{8}}{560}

1 2^{2} + 1 2^{2}

\frac{( 35 x ^{2} - 2 x - 24 )}{( 5 x + 4 )}

1 - \frac{1 + i}{1 - i}