展开 (5x^2+60x-5)/((x+1)(x-4)(x+5))

解答

展开

\frac{5 x ^{2} + 60 x - 5}{( x + 1 ) ( x - 4 ) ( x + 5 )}

\frac{5 x ^{2} + 60 x - 5}{x ^{3} + 2 x ^{2} - 19 x - 20}

求解步骤

\frac{5 x ^{2} + 60 x - 5}{( x + 1 ) ( x - 4 ) ( x + 5 )}

乘开

(x + 1) (x - 4) (x + 5) : x^{3} + 2 x^{2} - 19 x - 20

= \frac{5 x ^{2} + 60 x - 5}{x ^{3} + 2 x ^{2} - 19 x - 20}

e x p an d (x - y + 3 z = 0,) (2 x - 3 + z = 5)

e x p an d (\frac{1}{4} - 5 x)^{\frac{1}{2}}

e x p an d \frac{x ^{4} + ( p - 3 ) x ^{2} + ( q + 3 )}{x ^{2} + x + 1}

e x p an d \frac{3 ^{(n + 1) (n + 2)} + 65}{72}

e x p an d (1 - e^{- a t}) sin (x)