What is expand Dx(e^4+cos(3x)) ?

The solution to expand Dx(e^4+cos(3x)) is e^4Dx+Dxcos(3x)

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expand Dx(e^4+cos(3x))

expand

D x (e^{4} + cos (3 x))

e^{4} D x + D x cos (3 x)

Solution steps

D x (e^{4} + cos (3 x))

Apply the distributive law:

a (b + c) = ab + a c

a = D x, b = e^{4}, c = cos (3 x)

= D x e^{4} + D x cos (3 x)

= e^{4} D x + D x cos (3 x)

\frac{2 x ^{2} - 3}{( x ^{2} + 9 ) ( x ^{2} - 4 )}

\frac{2 x ^{2} - 2}{( x ^{2} + 1 ) ^{2}}

[(x + 1)^{2} - 2 y] d x - (x^{2} - 1) d y

(5 f + 3 e)^{2}

\frac{( 1 + x ^{n} )}{( 1 + x ) ^{n}}

What is expand Dx(e^4+cos(3x)) ?
The solution to expand Dx(e^4+cos(3x)) is e^4Dx+Dxcos(3x)