展开-sin(4x-3y)(4-3(dy)/(dx))

解答

展开

- sin (4 x - 3 y) (4 - 3 \frac{d y}{d x})

- 4 sin (4 x - 3 y) + 3 sin (4 x - 3 y) \frac{d y}{d x}

求解步骤

- sin (4 x - 3 y) (4 - 3 \frac{d y}{d x})

使用分配律:

a (b - c) = ab - a c

a = - sin (4 x - 3 y), b = 4, c = 3 \frac{d y}{d x}

= - sin (4 x - 3 y) \cdot 4 - (- sin (4 x - 3 y)) \cdot 3 \frac{d y}{d x}

使用加减运算法则

- (- a) = a

= - 4 sin (4 x - 3 y) + 3 sin (4 x - 3 y) \frac{d y}{d x}

e x p an d 1 + \frac{1}{4} + \frac{1}{9} + \frac{1}{16} + \frac{1}{25}

e x p an d \frac{k}{s ( s ^{2} + s + 1 ) ( s + 2 )}

e x p an d π (r + 3)^{2}

e x p an d \frac{( 2 x - 1 ) ( x + 1 )}{( x - 1 )}

e x p an d (x^{3} + 3 x^{2} + 6 x) e^{x}