展开 u(6,-3,6)

解答

展开

u (6, - 3, 6)

6 u, - 3 u, 6

求解步骤

u (6, - 3, 6)

= (6, - 3 \cdot 6,) u

使用分配律:

a (b - c) = ab - a c

a = u, b = 6,, c = 3, 6

= u \cdot 6, - u \cdot 3, 6

= 6 u, - 3 u, 6

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e x p an d (z - 1) (z - e^{- T})

e x p an d 2 (ln (x)) + 2 (l) + 2 (2 n - 1)

e x p an d \frac{- p + r}{( q - r ) ^{2}}

e x p an d (a + b + c + d + e + f + g)^{2}