結合する 1/(2ln(2))+1/(3ln(3))

解

結合する

\frac{1}{2 ln ( 2 )} + \frac{1}{3 ln ( 3 )}

\frac{1}{ln ( 4 )} + \frac{1}{ln ( 27 )}

十進法表記

1.02476 \dots

解答ステップ

\frac{1}{2 ln ( 2 )} + \frac{1}{3 ln ( 3 )}

対数の規則を適用する:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 ln (2) = ln (2^{2})

= \frac{1}{ln ( 2 ^{2} )} + \frac{1}{3 ln ( 3 )}

対数の規則を適用する:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 ln (3) = ln (3^{3})

= \frac{1}{ln ( 2 ^{2} )} + \frac{1}{ln ( 3 ^{3} )}

2^{2} = 4

= \frac{1}{ln ( 4 )} + \frac{1}{ln ( 3 ^{3} )}

3^{3} = 27

= \frac{1}{ln ( 4 )} + \frac{1}{ln ( 27 )}