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人気のある代数 >

(x-3)(x-2)=(x+5)(2x-3)+21

解

(x - 3) (x - 2) = (x + 5) (2 x - 3) + 21

解

x = - 12, x = 0

解答ステップ

(x - 3) (x - 2) = (x + 5) (2 x - 3) + 21

拡張

(x - 3) (x - 2) : x^{2} - 5 x + 6

拡張

(x + 5) (2 x - 3) + 21 : 2 x^{2} + 7 x + 6

x^{2} - 5 x + 6 = 2 x^{2} + 7 x + 6

6

を左側に移動します

x^{2} - 5 x = 2 x^{2} + 7 x

7 x

を左側に移動します

x^{2} - 12 x = 2 x^{2}

2 x^{2}

を左側に移動します

- x^{2} - 12 x = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 12)^{2} - 4 (- 1) \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 ( - 1 )}

解を分離する

x_{1} = \frac{- ( - 12 ) + 12}{2 ( - 1 )}, x_{2} = \frac{- ( - 12 ) - 12}{2 ( - 1 )}

x = \frac{- ( - 12 ) + 12}{2 ( - 1 )} : - 12

x = \frac{- ( - 12 ) - 12}{2 ( - 1 )} : 0

二次equationの解:

x = - 12, x = 0

グラフ

人気の例

completesquare x^2+6x+2=0

co m pl e t es q u a re x^{2} + 6 x + 2 = 0

9 x^{2} + 17 x - 2 = 0

(3x+2)^2=(2x+1)(2x-1)-2

(3 x + 2)^{2} = (2 x + 1) (2 x - 1) - 2

solvefor x,kx^2-kx+1-2x=0

so l v e f or x, k x^{2} - k x + 1 - 2 x = 0

solvefor x, x/y =(-3x^2+6x-3)/(2y)

so l v e f or x, \frac{x}{y} = \frac{- 3 x ^{2} + 6 x - 3}{2 y}