-16t^2-64t+512=0

解

- 16 t^{2} - 64 t + 512 = 0

t = - 8, t = 4

解答ステップ

- 16 t^{2} - 64 t + 512 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 64 ) \pm ( - 64 ) ^{2} - 4 ( - 16 ) \cdot 512}{2 ( - 16 )}

(- 64)^{2} - 4 (- 16) \cdot 512 = 192

t_{1, 2} = \frac{- ( - 64 ) \pm 192}{2 ( - 16 )}

解を分離する

t_{1} = \frac{- ( - 64 ) + 192}{2 ( - 16 )}, t_{2} = \frac{- ( - 64 ) - 192}{2 ( - 16 )}

t = \frac{- ( - 64 ) + 192}{2 ( - 16 )} : - 8

t = \frac{- ( - 64 ) - 192}{2 ( - 16 )} : 4

二次equationの解:

t = - 8, t = 4