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人気のある代数 >

(k+2)x^2-5x+5/2 =0

解

(k + 2) x^{2} - 5 x + \frac{5}{2} = 0

解

x = \frac{10 + - 40 k + 20}{2 ( 2 k + 4 )}, x = \frac{10 - - 40 k + 20}{2 ( 2 k + 4 )}; k \neq = - 2

解答ステップ

(k + 2) x^{2} - 5 x + \frac{5}{2} = 0

以下で両辺を乗じる:

2

2 x^{2} (k + 2) - 10 x + 5 = 0

拡張

2 x^{2} (k + 2) - 10 x + 5 : 2 k x^{2} + 4 x^{2} - 10 x + 5

2 k x^{2} + 4 x^{2} - 10 x + 5 = 0

標準的な形式で書く

a x^{2} + b x + c = 0

(2 k + 4) x^{2} - 10 x + 5 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( 2 k + 4 ) \cdot 5}{2 ( 2 k + 4 )}

簡素化

(- 10)^{2} - 4 (2 k + 4) \cdot 5 : - 40 k + 20

x_{1, 2} = \frac{- ( - 10 ) \pm - 40 k + 20}{2 ( 2 k + 4 )}; k \neq = - 2

解を分離する

x_{1} = \frac{- ( - 10 ) + - 40 k + 20}{2 ( 2 k + 4 )}, x_{2} = \frac{- ( - 10 ) - - 40 k + 20}{2 ( 2 k + 4 )}

x = \frac{- ( - 10 ) + - 40 k + 20}{2 ( 2 k + 4 )} : \frac{10 + - 40 k + 20}{2 ( 2 k + 4 )}

x = \frac{- ( - 10 ) - - 40 k + 20}{2 ( 2 k + 4 )} : \frac{10 - - 40 k + 20}{2 ( 2 k + 4 )}

二次equationの解:

x = \frac{10 + - 40 k + 20}{2 ( 2 k + 4 )}, x = \frac{10 - - 40 k + 20}{2 ( 2 k + 4 )}; k \neq = - 2

グラフ

人気の例

3.57x^2-160x+500=0

3.57 x^{2} - 160 x + 500 = 0

(x + 6)^{2} = 50

u^{2} + 6 u - 7 = 0

x (2 x + 1) = 15

solvefor x,ln(f)=x^2-1

so l v e f or x, ln (f) = x^{2} - 1