x/a+x/b =c,a\ne-b,a\ne 0,b\ne 0

解答

\frac{x}{a} + \frac{x}{b} = c, a \neq = - b, a \neq = 0, b \neq = 0

x = \frac{c ab}{b + a}; ab \neq = 0, a \neq = - b

求解步骤

\frac{x}{a} + \frac{x}{b} = c

乘以最小公倍数

b x + a x = c ab; ab \neq = 0

分解

b x + a x : x (b + a)

x (b + a) = c ab; ab \neq = 0

两边除以

b + a; ab \neq = 0, a \neq = - b

x = \frac{c ab}{b + a}; ab \neq = 0, a \neq = - b

f = \frac{3 ( 12 ) + 6}{7}

x = 0 + 2 \cdot 10 + \frac{1}{2} \cdot (- 0.2) \cdot 1 0^{2}

3 (j + 2 k) = 30

so l v e f or x, 4 x + 12 y = 20

\frac{x}{- 2} = - 2