faktorisieren x^6+216

Lösung

faktorisieren

x^{6} + 216

(x^{2} + 6) (x^{4} - 6 x^{2} + 36)

Schritte zur Lösung

x^{6} + 216

Wende Exponentenregel an

= (x^{2})^{3} + 6^{3}

Wende Formel zur Summe von dritten Potenzen an:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(x^{2})^{3} + 6^{3} = (x^{2} + 6) (x^{4} - 6 x^{2} + 6^{2})

= (x^{2} + 6) (x^{4} - 6 x^{2} + 6^{2})

6^{2} = 36

= (x^{2} + 6) (x^{4} - 6 x^{2} + 36)

f a c t or 64 - 343 x^{3}

e x p an d (x^{n} + y^{n})^{2}

s im pl i f y \frac{( x ^{2} - 2 x + 1 )}{( x ^{2} - 1 )}

e x p an d m^{2} (n^{2} + 4 n - 5) - m^{4} (n^{2} + 4 n - 5)

f a c t or a^{3} - a^{2} \cdot b + a \cdot b^{2} - b^{3}