vereinfachen (4x^4y^{-3})^{1/2}

Lösung

vereinfachen

(4 x^{4} y^{- 3})^{\frac{1}{2}}

\frac{2 x ^{2}}{y ^{\frac{3}{2}}}

Schritte zur Lösung

(4 x^{4} y^{- 3})^{\frac{1}{2}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(4 x^{4} y^{- 3})^{\frac{1}{2}} = 4^{\frac{1}{2}} (x^{4})^{\frac{1}{2}} (y^{- 3})^{\frac{1}{2}}

= 4^{\frac{1}{2}} (x^{4})^{\frac{1}{2}} (y^{- 3})^{\frac{1}{2}}

4^{\frac{1}{2}} = 2

= 2 (x^{4})^{\frac{1}{2}} (y^{- 3})^{\frac{1}{2}}

Vereinfache

(x^{4})^{\frac{1}{2}} : x^{2}

= 2 x^{2} (y^{- 3})^{\frac{1}{2}}

Vereinfache

(y^{- 3})^{\frac{1}{2}} : \frac{1}{y ^{\frac{3}{2}}}

= 2 x^{2} \frac{1}{y ^{\frac{3}{2}}}

Vereinfache

2 x^{2} \frac{1}{y ^{\frac{3}{2}}} : \frac{2 x ^{2}}{y ^{\frac{3}{2}}}

= \frac{2 x ^{2}}{y ^{\frac{3}{2}}}

f a c t or 8 x^{4} + 16 x^{3} - 4 x^{2}

s im pl i f y \frac{( x ^{2} - 4 x + 4 )}{( 2 x - 4 )}

e x p an d (7 x - 3 y)^{3}

s im pl i f y x^{3} - 3 x - 4 x - 12

s im pl i f y x^{3} \cdot y^{- 2}