de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Algebra >

(3x+2)(2x+2)(x+1)=2944

Lösung

(3 x + 2) (2 x + 2) (x + 1) = 2944

Lösung

x = 7, x = - \frac{29}{6} + i \frac{1679}{6}, x = - \frac{29}{6} - i \frac{1679}{6}

Schritte zur Lösung

(3 x + 2) (2 x + 2) (x + 1) = 2944

Schreibe

(3 x + 2) (2 x + 2) (x + 1)

um:

6 x^{3} + 16 x^{2} + 14 x + 4

6 x^{3} + 16 x^{2} + 14 x + 4 = 2944

Verschiebe

2944

auf die linke Seite

6 x^{3} + 16 x^{2} + 14 x - 2940 = 0

Faktorisiere

6 x^{3} + 16 x^{2} + 14 x - 2940 : 2 (x - 7) (3 x^{2} + 29 x + 210)

2 (x - 7) (3 x^{2} + 29 x + 210) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x - 7 = 0 or 3 x^{2} + 29 x + 210 = 0

Löse

x - 7 = 0 : x = 7

Löse

3 x^{2} + 29 x + 210 = 0 : x = - \frac{29}{6} + i \frac{1679}{6}, x = - \frac{29}{6} - i \frac{1679}{6}

Die Lösungen sind

x = 7, x = - \frac{29}{6} + i \frac{1679}{6}, x = - \frac{29}{6} - i \frac{1679}{6}

Graph

Beliebte Beispiele

x^3-3x^2+2x-6=0

x^{3} - 3 x^{2} + 2 x - 6 = 0

5x^3+3x^2-7x+8=0

5 x^{3} + 3 x^{2} - 7 x + 8 = 0

2 x^{4} - x^{2} - 6 = 0

(x^2+2x-14)^5=1

(x^{2} + 2 x - 14)^{5} = 1

m^{3} - 2 m + 1 = 0