solvefor c,c^1c^2=r^1+r^2

Lösung

löse nach

c, c^{1} c^{2} = r^{1} + r^{2}

c = 3 r + r^{2}, c = - \frac{3 r + r ^{2}}{2} + \frac{3 r + r ^{2} 3}{2} i, c = - \frac{3 r + r ^{2}}{2} - \frac{3 r + r ^{2} 3}{2} i

Schritte zur Lösung

c^{1} c^{2} = r^{1} + r^{2}

Vereinfache

c^{3} = r + r^{2}

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

c = 3 r + r^{2}, c = 3 r + r^{2} \frac{- 1 + 3 i}{2}, c = 3 r + r^{2} \frac{- 1 - 3 i}{2}

Vereinfache

3 r + r^{2} \frac{- 1 + 3 i}{2} : - \frac{3 r + r ^{2}}{2} + \frac{3 r + r ^{2} 3}{2} i

Vereinfache

3 r + r^{2} \frac{- 1 - 3 i}{2} : - \frac{3 r + r ^{2}}{2} - \frac{3 r + r ^{2} 3}{2} i

c = 3 r + r^{2}, c = - \frac{3 r + r ^{2}}{2} + \frac{3 r + r ^{2} 3}{2} i, c = - \frac{3 r + r ^{2}}{2} - \frac{3 r + r ^{2} 3}{2} i

x^{7} = 120

x^{4} - 2 = 0

x^{4} + x^{3} - 2 x^{2} - 3 x - 3 = 0

x^{7} - x^{5} = - 11

2 (2 x + 1) (x^{2} + 1) = 0