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Beliebt Algebra >

(x^2+5)(x-1)-(x^2+5)(2x+3)=0

Lösung

(x^{2} + 5) (x - 1) - (x^{2} + 5) (2 x + 3) = 0

Lösung

x = - 4, x = 5 i, x = - 5 i

Schritte zur Lösung

(x^{2} + 5) (x - 1) - (x^{2} + 5) (2 x + 3) = 0

Faktorisiere

(x^{2} + 5) (x - 1) - (x^{2} + 5) (2 x + 3) : - (x + 4) (x^{2} + 5)

- (x + 4) (x^{2} + 5) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x + 4 = 0 or x^{2} + 5 = 0

Löse

x + 4 = 0 : x = - 4

Löse

x^{2} + 5 = 0 : x = 5 i, x = - 5 i

Die Lösungen sind

x = - 4, x = 5 i, x = - 5 i

Graph

Beliebte Beispiele

(5x+3)^{28}= 16/7

(5 x + 3)^{28} = \frac{16}{7}

- x^{3} + 27 x - 54 x = 0

(x-2)^6+(x-4)^6=64

(x - 2)^{6} + (x - 4)^{6} = 64

solvefor x,f(x)^4+f(-x)^4=x^{2000}

so l v e f or x, f (x)^{4} + f (- x)^{4} = x^{2000}

2a^3-3a^2+2a+1=0

2 a^{3} - 3 a^{2} + 2 a + 1 = 0