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人気のある代数 >

x^2-(k+2)x+(k+5)=0

解

x^{2} - (k + 2) x + (k + 5) = 0

解

x = \frac{k + 2 + k ^{2} - 16}{2}, x = \frac{k + 2 - k ^{2} - 16}{2}

解答ステップ

x^{2} - (k + 2) x + (k + 5) = 0

拡張

x^{2} - (k + 2) x + (k + 5) : x^{2} - k x - 2 x + k + 5

x^{2} - k x - 2 x + k + 5 = 0

標準的な形式で書く

a x^{2} + b x + c = 0

x^{2} - (k + 2) x + k + 5 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - k - 2 ) \pm ( - k - 2 ) ^{2} - 4 \cdot 1 \cdot ( k + 5 )}{2 \cdot 1}

簡素化

(- k - 2)^{2} - 4 \cdot 1 \cdot (k + 5) : k^{2} - 16

x_{1, 2} = \frac{- ( - k - 2 ) \pm k ^{2} - 16}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - k - 2 ) + k ^{2} - 16}{2 \cdot 1}, x_{2} = \frac{- ( - k - 2 ) - k ^{2} - 16}{2 \cdot 1}

x = \frac{- ( - k - 2 ) + k ^{2} - 16}{2 \cdot 1} : \frac{k + 2 + k ^{2} - 16}{2}

x = \frac{- ( - k - 2 ) - k ^{2} - 16}{2 \cdot 1} : \frac{k + 2 - k ^{2} - 16}{2}

二次equationの解:

x = \frac{k + 2 + k ^{2} - 16}{2}, x = \frac{k + 2 - k ^{2} - 16}{2}

グラフ

人気の例

solvefor a,a^2+b^2+2(3a+2b)+13=0

so l v e f or a, a^{2} + b^{2} + 2 (3 a + 2 b) + 13 = 0

solvefor p,z=p^2+q^2

so l v e f or p, z = p^{2} + q^{2}

solvefor x,f1^*(x)=x^2-2x-8

so l v e f or x, f 1^{\cdot} (x) = x^{2} - 2 x - 8

3sqrt(2)*x^2-5x-sqrt(2)=0

32 \cdot x^{2} - 5 x - 2 = 0

6sqrt(3)*x^2+7x=sqrt(3)

63 \cdot x^{2} + 7 x = 3