ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある代数 >

solvefor x,p^2+q^2=x^2+y^2

解

解く

x, p^{2} + q^{2} = x^{2} + y^{2}

解

x = p^{2} + q^{2} - y^{2}, x = - p^{2} + q^{2} - y^{2}

解答ステップ

p^{2} + q^{2} = x^{2} + y^{2}

辺を交換する

x^{2} + y^{2} = p^{2} + q^{2}

y^{2}

を右側に移動します

x^{2} = p^{2} + q^{2} - y^{2}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

x = p^{2} + q^{2} - y^{2}, x = - p^{2} + q^{2} - y^{2}

グラフ

人気の例

solvefor y,x^3-x*y^2+3y^2+2=0

so l v e f or y, x^{3} - x \cdot y^{2} + 3 y^{2} + 2 = 0

solvefor x,f(1+x)(x-5)=y

so l v e f or x, f (1 + x) (x - 5) = y

4x^2-2(a^2+b^2)x+a^2b^2=0

4 x^{2} - 2 (a^{2} + b^{2}) x + a^{2} b^{2} = 0

solvefor x,f(x+5)=x^2+4x+3

so l v e f or x, f (x + 5) = x^{2} + 4 x + 3

(k-12)*x^2+2(k-12)x+2=0

(k - 12) \cdot x^{2} + 2 (k - 12) x + 2 = 0