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人気のある代数 >

solvefor a,(a+b)1+a^2=c^6

解

解く

a, (a + b) 1 + a^{2} = c^{6}

解

a = \frac{- 1 + 1 - 4 ( b - c ^{6} )}{2}, a = \frac{- 1 - 1 - 4 ( b - c ^{6} )}{2}

解答ステップ

(a + b) \cdot 1 + a^{2} = c^{6}

拡張

(a + b) \cdot 1 + a^{2} : a + b + a^{2}

a + b + a^{2} = c^{6}

c^{6}

を左側に移動します

a + b + a^{2} - c^{6} = 0

標準的な形式で書く

a x^{2} + b x + c = 0

a^{2} + a + b - c^{6} = 0

解くとthe二次式

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( b - c ^{6} )}{2 \cdot 1}

簡素化

1^{2} - 4 \cdot 1 \cdot (b - c^{6}) : 1 - 4 (b - c^{6})

a_{1, 2} = \frac{- 1 \pm 1 - 4 ( b - c ^{6} )}{2 \cdot 1}

解を分離する

a_{1} = \frac{- 1 + 1 - 4 ( b - c ^{6} )}{2 \cdot 1}, a_{2} = \frac{- 1 - 1 - 4 ( b - c ^{6} )}{2 \cdot 1}

a = \frac{- 1 + 1 - 4 ( b - c ^{6} )}{2 \cdot 1} : \frac{- 1 + 1 - 4 ( b - c ^{6} )}{2}

a = \frac{- 1 - 1 - 4 ( b - c ^{6} )}{2 \cdot 1} : \frac{- 1 - 1 - 4 ( b - c ^{6} )}{2}

二次equationの解:

a = \frac{- 1 + 1 - 4 ( b - c ^{6} )}{2}, a = \frac{- 1 - 1 - 4 ( b - c ^{6} )}{2}

グラフ

人気の例

solvefor k,p^2+q^2=k^2

so l v e f or k, p^{2} + q^{2} = k^{2}

(k-12)*x^2+2(k-12)*x+2=0

(k - 12) \cdot x^{2} + 2 (k - 12) \cdot x + 2 = 0

sqrt(2)*x^2+7x+5sqrt(2)=0

2 \cdot x^{2} + 7 x + 52 = 0

solvefor x,x^2*p^2+y^2*q^2=z^2

so l v e f or x, x^{2} \cdot p^{2} + y^{2} \cdot q^{2} = z^{2}

(x + 2)^{3} = x^{3} - 8