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受欢迎的代数 >

solvefor x,x^2p^2+y^2q^2=z^2

解答

求解

x, x^{2} \cdot p^{2} + y^{2} \cdot q^{2} = z^{2}

解答

x = \frac{z ^{2} - y ^{2} q ^{2}}{p}, x = - \frac{z ^{2} - y ^{2} q ^{2}}{p}; p \neq = 0

求解步骤

x^{2} p^{2} + y^{2} q^{2} = z^{2}

将

y^{2} \cdot q^{2}

到右边

x^{2} p^{2} = z^{2} - y^{2} q^{2}

两边除以

p^{2}; p \neq = 0

x^{2} = \frac{z ^{2} - y ^{2} q ^{2}}{p ^{2}}; p \neq = 0

对于

x^{2} = f (a)

解为

x = f (a), - f (a)

x = \frac{z ^{2} - y ^{2} q ^{2}}{p ^{2}}, x = - \frac{z ^{2} - y ^{2} q ^{2}}{p ^{2}}; p \neq = 0

化简

\frac{z ^{2} - y ^{2} q ^{2}}{p ^{2}} : \frac{z ^{2} - y ^{2} q ^{2}}{p}

化简

- \frac{z ^{2} - y ^{2} q ^{2}}{p ^{2}} : - \frac{z ^{2} - y ^{2} q ^{2}}{p}

x = \frac{z ^{2} - y ^{2} q ^{2}}{p}, x = - \frac{z ^{2} - y ^{2} q ^{2}}{p}; p \neq = 0

作图

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