x^2-(1+sqrt(2))*x+sqrt(2)=0

解答

x^{2} - (1 + 2) \cdot x + 2 = 0

x = 2, x = 1

十进制

x = 1.41421 \dots, x = 1

求解步骤

x^{2} - (1 + 2) x + 2 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 1 - 2 ) \pm ( - 1 - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 1 - 2)^{2} - 4 \cdot 1 \cdot 2 = 2 - 1

x_{1, 2} = \frac{- ( - 1 - 2 ) \pm ( 2 - 1 )}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 1 - 2 ) + 2 - 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 - 2 ) - ( 2 - 1 )}{2 \cdot 1}

x = \frac{- ( - 1 - 2 ) + 2 - 1}{2 \cdot 1} : 2

x = \frac{- ( - 1 - 2 ) - ( 2 - 1 )}{2 \cdot 1} : 1

二次方程组的解是:

x = 2, x = 1

\frac{( x ^{2} )}{6} - \frac{( 3 x )}{6} = 3 (x - 5)

4 x^{2} - 4 a^{2} \cdot x + (a^{4} - b^{4}) = 0

so l v e f or x, x^{2} - 10 x + y^{2} - 20 y = - 125

so l v e f or x, z = (5 x + 3) (6 x + 2 y)

\frac{3 \cdot x ^{2} - 2 x + 1}{2} = 0