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人気のある代数 >

solvefor x,(p+1)x^2-2(p+3)x+3p=0

解

解く

x, (p + 1) x^{2} - 2 (p + 3) x + 3 p = 0

解

x = \frac{p + 3 + - 2 p ^{2} + 3 p + 9}{p + 1}, x = \frac{p + 3 - - 2 p ^{2} + 3 p + 9}{p + 1}; p \neq = - 1

解答ステップ

(p + 1) x^{2} - 2 (p + 3) x + 3 p = 0

拡張

(p + 1) x^{2} - 2 (p + 3) x + 3 p : x^{2} p + x^{2} - 2 x p - 6 x + 3 p

x^{2} p + x^{2} - 2 x p - 6 x + 3 p = 0

標準的な形式で書く

a x^{2} + b x + c = 0

(p + 1) x^{2} - (2 p + 6) x + 3 p = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 2 p - 6 ) \pm ( - 2 p - 6 ) ^{2} - 4 ( p + 1 ) \cdot 3 p}{2 ( p + 1 )}

簡素化

(- 2 p - 6)^{2} - 4 (p + 1) \cdot 3 p : 2 - 2 p^{2} + 3 p + 9

x_{1, 2} = \frac{- ( - 2 p - 6 ) \pm 2 - 2 p ^{2} + 3 p + 9}{2 ( p + 1 )}; p \neq = - 1

解を分離する

x_{1} = \frac{- ( - 2 p - 6 ) + 2 - 2 p ^{2} + 3 p + 9}{2 ( p + 1 )}, x_{2} = \frac{- ( - 2 p - 6 ) - 2 - 2 p ^{2} + 3 p + 9}{2 ( p + 1 )}

x = \frac{- ( - 2 p - 6 ) + 2 - 2 p ^{2} + 3 p + 9}{2 ( p + 1 )} : \frac{p + 3 + - 2 p ^{2} + 3 p + 9}{p + 1}

x = \frac{- ( - 2 p - 6 ) - 2 - 2 p ^{2} + 3 p + 9}{2 ( p + 1 )} : \frac{p + 3 - - 2 p ^{2} + 3 p + 9}{p + 1}

二次equationの解:

x = \frac{p + 3 + - 2 p ^{2} + 3 p + 9}{p + 1}, x = \frac{p + 3 - - 2 p ^{2} + 3 p + 9}{p + 1}; p \neq = - 1

グラフ

人気の例

(z-i)^3=(z+1)^3

(z - i)^{3} = (z + 1)^{3}

2= 1/1-(v^2)/(c^2)

2 = \frac{1}{1} - \frac{v ^{2}}{c ^{2}}

sqrt(2)*x^2-3x-2sqrt(2)=0

2 \cdot x^{2} - 3 x - 22 = 0

(3x-1)^2-(2x+3)^2=0

(3 x - 1)^{2} - (2 x + 3)^{2} = 0

(x - a)^{2} = b