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人気のある代数 >

solvefor m,m(m+1)=n(n+2)

解

解く

m, m (m + 1) = n (n + 2)

解

m = \frac{- 1 + 1 - 4 ( - 2 n - n ^{2} )}{2}, m = \frac{- 1 - 1 - 4 ( - 2 n - n ^{2} )}{2}

解答ステップ

m (m + 1) = n (n + 2)

拡張

m (m + 1) : m^{2} + m

拡張

n (n + 2) : n^{2} + 2 n

m^{2} + m = n^{2} + 2 n

2 n

を左側に移動します

m^{2} + m - 2 n = n^{2}

n^{2}

を左側に移動します

m^{2} + m - 2 n - n^{2} = 0

解くとthe二次式

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 n - n ^{2} )}{2 \cdot 1}

簡素化

1^{2} - 4 \cdot 1 \cdot (- 2 n - n^{2}) : 1 - 4 (- 2 n - n^{2})

m_{1, 2} = \frac{- 1 \pm 1 - 4 ( - 2 n - n ^{2} )}{2 \cdot 1}

解を分離する

m_{1} = \frac{- 1 + 1 - 4 ( - 2 n - n ^{2} )}{2 \cdot 1}, m_{2} = \frac{- 1 - 1 - 4 ( - 2 n - n ^{2} )}{2 \cdot 1}

m = \frac{- 1 + 1 - 4 ( - 2 n - n ^{2} )}{2 \cdot 1} : \frac{- 1 + 1 - 4 ( - 2 n - n ^{2} )}{2}

m = \frac{- 1 - 1 - 4 ( - 2 n - n ^{2} )}{2 \cdot 1} : \frac{- 1 - 1 - 4 ( - 2 n - n ^{2} )}{2}

二次equationの解:

m = \frac{- 1 + 1 - 4 ( - 2 n - n ^{2} )}{2}, m = \frac{- 1 - 1 - 4 ( - 2 n - n ^{2} )}{2}

グラフ

人気の例

solvefor x,z=6x^2-3xy-2y^2

so l v e f or x, z = 6 x^{2} - 3 x y - 2 y^{2}

solvefor x,(x+y+z)^3=x^3+y^3+z^3

so l v e f or x, (x + y + z)^{3} = x^{3} + y^{3} + z^{3}

2x^0-13x^2+26x-24=0

2 x^{0} - 13 x^{2} + 26 x - 24 = 0

(d - x)^{2} = 2 x^{2}

(a+b)^2x^2+(a-b)^2=0

(a + b)^{2} x^{2} + (a - b)^{2} = 0