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人気のある代数 >

solvefor x,p=(x-1)(x+1)p(2)

解

解く

x, p = (x - 1) (x + 1) p (2)

解

x = \frac{- p ( 2 ) ( - p - p ( 2 ) )}{p ( 2 )}, x = - \frac{- p ( 2 ) ( - p - p ( 2 ) )}{p ( 2 )}; p (2) \neq = 0

解答ステップ

p = (x - 1) (x + 1) p (2)

拡張

(x - 1) (x + 1) p (2) : x^{2} p (2) - p (2)

p = x^{2} p (2) - p (2)

辺を交換する

x^{2} p (2) - p (2) = p

p

を左側に移動します

x^{2} p (2) - p (2) - p = 0

標準的な形式で書く

a x^{2} + b x + c = 0

p (2) x^{2} - p (2) - p = 0

解くとthe二次式

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 p ( 2 ) ( - p ( 2 ) - p )}{2 p ( 2 )}

簡素化

0^{2} - 4 p (2) (- p (2) - p) : 2 - p (2) (- p - p (2))

x_{1, 2} = \frac{- 0 \pm 2 - p ( 2 ) ( - p - p ( 2 ) )}{2 p ( 2 )}; p (2) \neq = 0

解を分離する

x_{1} = \frac{- 0 + 2 - p ( 2 ) ( - p - p ( 2 ) )}{2 p ( 2 )}, x_{2} = \frac{- 0 - 2 - p ( 2 ) ( - p - p ( 2 ) )}{2 p ( 2 )}

x = \frac{- 0 + 2 - p ( 2 ) ( - p - p ( 2 ) )}{2 p ( 2 )} : \frac{- p ( 2 ) ( - p - p ( 2 ) )}{p ( 2 )}

x = \frac{- 0 - 2 - p ( 2 ) ( - p - p ( 2 ) )}{2 p ( 2 )} : - \frac{- p ( 2 ) ( - p - p ( 2 ) )}{p ( 2 )}

二次equationの解:

x = \frac{- p ( 2 ) ( - p - p ( 2 ) )}{p ( 2 )}, x = - \frac{- p ( 2 ) ( - p - p ( 2 ) )}{p ( 2 )}; p (2) \neq = 0

グラフ

人気の例

x^{2} - 18 x - 77 = 0

4 t (3 - t) = 4 t + 3

(a + c) (a - c) = 0

solvefor x,((p-3)(p+5))*x^2-4x+8=0

so l v e f or x, ((p - 3) (p + 5)) \cdot x^{2} - 4 x + 8 = 0

xlog_{10}(10)(x-3)=2

x lo g_{10} (10) (x - 3) = 2