x^2+(m-1)x+(m+2)=0

Lösung

x^{2} + (m - 1) x + (m + 2) = 0

x = \frac{- m + 1 + m ^{2} - 6 m - 7}{2}, x = \frac{- m + 1 - m ^{2} - 6 m - 7}{2}

Schritte zur Lösung

x^{2} + (m - 1) x + (m + 2) = 0

Schreibe

x^{2} + (m - 1) x + (m + 2)

um:

x^{2} + m x - x + m + 2

x^{2} + m x - x + m + 2 = 0

Schreibe in der Standard Form

a x^{2} + b x + c = 0

x^{2} + (m - 1) x + m + 2 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- ( m - 1 ) \pm ( m - 1 ) ^{2} - 4 \cdot 1 \cdot ( m + 2 )}{2 \cdot 1}

Vereinfache

(m - 1)^{2} - 4 \cdot 1 \cdot (m + 2) : m^{2} - 6 m - 7

x_{1, 2} = \frac{- ( m - 1 ) \pm m ^{2} - 6 m - 7}{2 \cdot 1}

Trenne die Lösungen

x_{1} = \frac{- ( m - 1 ) + m ^{2} - 6 m - 7}{2 \cdot 1}, x_{2} = \frac{- ( m - 1 ) - m ^{2} - 6 m - 7}{2 \cdot 1}

x = \frac{- ( m - 1 ) + m ^{2} - 6 m - 7}{2 \cdot 1} : \frac{- m + 1 + m ^{2} - 6 m - 7}{2}

x = \frac{- ( m - 1 ) - m ^{2} - 6 m - 7}{2 \cdot 1} : \frac{- m + 1 - m ^{2} - 6 m - 7}{2}

Die Lösungen für die quadratische Gleichung sind:

x = \frac{- m + 1 + m ^{2} - 6 m - 7}{2}, x = \frac{- m + 1 - m ^{2} - 6 m - 7}{2}

so l v e f or a, 130 r^{2} - a^{2} r^{3} + a^{2} = 0

(3) x = (x^{2} = 9 - 3 = 5)

(2 x - 3)^{2} - (x + 5)^{2} = 0

0.5 x^{2} - 3 x = - x + 2.5

e = x^{2} - 3 x + 5