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受欢迎的代数 >

a^{12}x+4x=-3x^2+x-5

解答

a^{12} x + 4 x = - 3 x^{2} + x - 5

解答

x = - \frac{3 + a ^{12} + a ^{24} + 6 a ^{12} - 51}{6}, x = - \frac{3 + a ^{12} - a ^{24} + 6 a ^{12} - 51}{6}

求解步骤

a^{12} x + 4 x = - 3 x^{2} + x - 5

交换两边

- 3 x^{2} + x - 5 = a^{12} x + 4 x

将

4 x

para o lado esquerdo

- 3 x^{2} - 3 x - 5 = a^{12} x

将

a^{12} x

para o lado esquerdo

- 3 x^{2} - 3 x - 5 - a^{12} x = 0

改写成标准形式

a x^{2} + b x + c = 0

- 3 x^{2} - (3 + a^{12}) x - 5 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 3 - a ^{12} ) \pm ( - 3 - a ^{12} ) ^{2} - 4 ( - 3 ) ( - 5 )}{2 ( - 3 )}

化简

(- 3 - a^{12})^{2} - 4 (- 3) (- 5) : a^{24} + 6 a^{12} - 51

x_{1, 2} = \frac{- ( - 3 - a ^{12} ) \pm a ^{24} + 6 a ^{12} - 51}{2 ( - 3 )}

将解分隔开

x_{1} = \frac{- ( - 3 - a ^{12} ) + a ^{24} + 6 a ^{12} - 51}{2 ( - 3 )}, x_{2} = \frac{- ( - 3 - a ^{12} ) - a ^{24} + 6 a ^{12} - 51}{2 ( - 3 )}

x = \frac{- ( - 3 - a ^{12} ) + a ^{24} + 6 a ^{12} - 51}{2 ( - 3 )} : - \frac{3 + a ^{12} + a ^{24} + 6 a ^{12} - 51}{6}

x = \frac{- ( - 3 - a ^{12} ) - a ^{24} + 6 a ^{12} - 51}{2 ( - 3 )} : - \frac{3 + a ^{12} - a ^{24} + 6 a ^{12} - 51}{6}

二次方程组的解是:

x = - \frac{3 + a ^{12} + a ^{24} + 6 a ^{12} - 51}{6}, x = - \frac{3 + a ^{12} - a ^{24} + 6 a ^{12} - 51}{6}

作图

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