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受欢迎的代数 >

solvefor x,f=f(x^2)-2f(1)

解答

求解

x, f = f (x^{2}) - 2 f (1)

解答

x = \frac{f + 2 f ( 1 )}{f}, x = - \frac{f + 2 f ( 1 )}{f}; f \neq = 0

求解步骤

f = f (x^{2}) - 2 f (1)

整理后得

f = x^{2} f - 2 f (1)

交换两边

x^{2} f - 2 f (1) = f

将

2 f (1)

到右边

x^{2} f = f + 2 f (1)

两边除以

f; f \neq = 0

x^{2} = \frac{f + 2 f ( 1 )}{f}; f \neq = 0

对于

x^{2} = f (a)

解为

x = f (a), - f (a)

x = \frac{f + 2 f ( 1 )}{f}, x = - \frac{f + 2 f ( 1 )}{f}; f \neq = 0

作图

流行的例子

solvefor x,x^2+y^2+z^2-25=0

so l v e f or x, x^{2} + y^{2} + z^{2} - 25 = 0

- x^{2} + 10 x + 24 = 0

solvefor x,g=2x^2+x-3g(-2)

so l v e f or x, g = 2 x^{2} + x - 3 g (- 2)

x^{2} - 1 = x - 2

4x^1+2x^2=2,3x^1-6x^2=6

4 x^{1} + 2 x^{2} = 2, 3 x^{1} - 6 x^{2} = 6