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受欢迎的代数 >

2p+p^2=1358

解答

2 p + p^{2} = 1358

解答

p = - 1 + 3151, p = - 1 - 3151

+1

十进制

p = 35.86461 \dots, p = - 37.86461 \dots

求解步骤

2 p + p^{2} = 1358

将

1358

para o lado esquerdo

2 p + p^{2} - 1358 = 0

改写成标准形式

a x^{2} + b x + c = 0

p^{2} + 2 p - 1358 = 0

使用求根公式求解

p_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 1358 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 1358) = 6151

p_{1, 2} = \frac{- 2 \pm 6 151}{2 \cdot 1}

将解分隔开

p_{1} = \frac{- 2 + 6 151}{2 \cdot 1}, p_{2} = \frac{- 2 - 6 151}{2 \cdot 1}

p = \frac{- 2 + 6 151}{2 \cdot 1} : - 1 + 3151

p = \frac{- 2 - 6 151}{2 \cdot 1} : - 1 - 3151

二次方程组的解是:

p = - 1 + 3151, p = - 1 - 3151

作图

流行的例子

x^2+(m-1)*x+2m-6=0

x^{2} + (m - 1) \cdot x + 2 m - 6 = 0

x^{2} = - 3, x^{1} = 7

25m^2-54m+128=0

25 m^{2} - 54 m + 128 = 0

solvefor a,a^2+b^2-2(3a+2b)+13=0

so l v e f or a, a^{2} + b^{2} - 2 (3 a + 2 b) + 13 = 0

solvefor x,x^2+25y^2-2x+10y+2=0

so l v e f or x, x^{2} + 25 y^{2} - 2 x + 10 y + 2 = 0