2^a=5

Lösung

2^{a} = 5

a = \frac{ln ( 5 )}{ln ( 2 )}

Dezimale

a = 2.32192 \dots

Schritte zur Lösung

2^{a} = 5

Wende Exponentenregel an

a ln (2) = ln (5)

Löse

a ln (2) = ln (5) : a = \frac{ln ( 5 )}{ln ( 2 )}

a = \frac{ln ( 5 )}{ln ( 2 )}

2 x + 2^{- x + 6} - 20 = 0

10 \cdot (0.5)^{x} - 2^{3} - x = 64

3^{x} + 3^{x} = 54

4 x = 2^{x}

so l v e f or x, [t] = [p^{x} \cdot d^{y} \cdot e^{2}]