2^{x-3}=128

Lösung

2^{x - 3} = 128

x = 10

Schritte zur Lösung

2^{x - 3} = 128

Wende Exponentenregel an

x - 3 = 7

Löse

x - 3 = 7 : x = 10

x = 10

(7^{x + 1})^{\frac{1}{5}} = 7

2^{x} + 1 + 2^{x} + 2 = 48

3^{x + 7} = 9^{x + 1}

so l v e f or x, 3^{x} + 2^{y} = 1 + 2^{z}

e^{x} \cdot (1 + e^{x}) = \frac{3}{4}