3^{2x-5}+9^{x-2}=4

Lösung

3^{2 x - 5} + 9^{x - 2} = 4

x = \frac{5}{2}

Dezimale

x = 2.5

Schritte zur Lösung

3^{2 x - 5} + 9^{x - 2} = 4

Wende Exponentenregel an

2 x = 5

Löse

2 x = 5 : x = \frac{5}{2}

x = \frac{5}{2}

(\frac{1}{16})^{x} = (\frac{1}{8})^{6}

3^{x + 1} = 81

2^{x} + 2^{x - 1} = 48

e^{2} x - e^{x} = 56

74 = \frac{10 + 250 ( 0.6 ) ^{t}}{8}