(x^2+1)/(x^2-5(x+1/x)+8)=0

Lösung

\frac{x ^{2} + 1}{x ^{2} - 5 ( x + \frac{1}{x} ) + 8} = 0

x = i, x = - i

Schritte zur Lösung

\frac{x ^{2} + 1}{x ^{2} - 5 ( x + \frac{1}{x} ) + 8} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} + 1 = 0

Löse

x^{2} + 1 = 0 : x = i, x = - i

x = i, x = - i

\frac{x + 1}{x} = \frac{21}{20}

x x^{3} + \frac{\frac{x}{1}}{\frac{5}{x}} = \frac{9}{10}

\frac{31}{2 - 4 ( 2 x - 3 )} = \frac{1}{3 ( \frac{3}{4} - 6 x )}

p + 3 = \frac{1}{( p ^{2} )}

x^{- 3} = \frac{27}{64}