solvefor x,f(x)^{-1}=((4x-3))/((x+4))

解

解く

x, f (x)^{- 1} = \frac{( 4 x - 3 )}{( x + 4 )}

x = \frac{3 + f + f ^{2} + 70 f + 9}{8}, x = \frac{3 + f - f ^{2} + 70 f + 9}{8}

解答ステップ

f x^{- 1} = \frac{( 4 x - 3 )}{( x + 4 )}

改良

\frac{f}{x} = \frac{4 x - 3}{x + 4}

たすき掛け

f (x + 4) = x (4 x - 3)

解く

f (x + 4) = x (4 x - 3) : x = \frac{3 + f + f ^{2} + 70 f + 9}{8}, x = \frac{3 + f - f ^{2} + 70 f + 9}{8}

x = \frac{3 + f + f ^{2} + 70 f + 9}{8}, x = \frac{3 + f - f ^{2} + 70 f + 9}{8}