2((x^2+1}{x^2})-3(\frac{x-1)/x)-4=0

解答

2 (\frac{x ^{2} + 1}{x ^{2}}) - 3 (\frac{x - 1}{x}) - 4 = 0

x = - \frac{2}{5}, x = 1

十进制

x = - 0.4, x = 1

求解步骤

2 (\frac{x ^{2} + 1}{x ^{2}}) - 3 (\frac{x - 1}{x}) - 4 = 0

乘以最小公倍数

2 (x^{2} + 1) - 3 x (x - 1) - 4 x^{2} = 0

解

2 (x^{2} + 1) - 3 x (x - 1) - 4 x^{2} = 0 : x = - \frac{2}{5}, x = 1

x = - \frac{2}{5}, x = 1

验证解

找到无定义的点（奇点）:

x = 0

将不在定义域的点与解相综合:

x = - \frac{2}{5}, x = 1

so l v e f or x, (\frac{1}{x}) - (\frac{1}{y}) - 2 = 0

so l v e f or y, 3 x^{2} y^{4} = 5 x^{3} y^{- 3} z^{2}

\frac{( 1 + x ^{4} + x ^{8} )}{x ^{4}} = 4

\frac{2 ( x + 1 )}{3 + 4 ( x - 2 )} = \frac{x}{2 + 5}

\frac{3 x - 2}{x} = \frac{59 x ^{2} - 4}{x ^{2}}