faktorisieren (a+b+c)(ab+bc+ac)-abc

Lösung

faktorisieren

(a + b + c) (ab + b c + a c) - ab c

a^{2} b + a^{2} c + a b^{2} + a c^{2} + 2 ab c + b c^{2} + b^{2} c

Schritte zur Lösung

(a + b + c) (ab + b c + a c) - ab c

Multipliziere aus

(a + b + c) (ab + b c + a c) : a^{2} b + a b^{2} + 3 ab c + a^{2} c + a c^{2} + b^{2} c + b c^{2}

= a^{2} b + a b^{2} + 3 ab c + a^{2} c + a c^{2} + b^{2} c + b c^{2} - ab c

Vereinfache

a^{2} b + a b^{2} + 3 ab c + a^{2} c + a c^{2} + b^{2} c + b c^{2} - ab c : a^{2} b + a^{2} c + a b^{2} + a c^{2} + 2 ab c + b c^{2} + b^{2} c

= a^{2} b + a^{2} c + a b^{2} + a c^{2} + 2 ab c + b c^{2} + b^{2} c

f a c t or e^{x - 4 t} + e^{x + 4 t}

f a c t or 2 ab c - 3 ab - 4 x c + 6 x

f a c t or \frac{15 3 5 - 3}{4}

f a c t or (y + z)^{3} + 27

f a c t or y^{2} + 0.4 y - 0.05