因式分解 H^2Te+I(OH)7

解答

因式分解

H^{2} T e + I (O H) 7

H (eH T + 7 I O)

求解步骤

H^{2} T e + I (O H) \cdot 7

去除括号:

(a) = a

= H^{2} T e + I O H \cdot 7

使用指数法则:

a^{b + c} = a^{b} a^{c}

H^{2} = HH

= HH T e + 7 I O H

因式分解出通项

H

= H (H T e + 7 I O)

f a c t or 200 \cdot (e^{2})

f a c t or (x^{8} y^{8}) - 1

f a c t or x^{2} - 16 x + (- 8)

f a c t or e^{10 x^{2} + 4 y^{2} + 8}

f a c t or 6 (2 p + q)^{2} + (2 p + q)^{- 2}