展开 (3x+2)(1+1=0)

解答

展开

(3 x + 2) (1 + 1 = 0)

6 x = 0

求解步骤

(3 x + 2) (1 + 1 = 0)

= (1 + 1 \cdot 0 =) (3 x + 2)

使用 FOIL 方法:

(a + b) (c + d) = a c + a d + b c + b d

a = 3 x, b = 2, c = 1, d = 1 = 0

3 x \cdot 1 + 3 x \cdot 1 = 0 + 2 \cdot 1 + 2 \cdot 1 = 0

3 \cdot 1 \cdot x + 3 \cdot 1 \cdot x = 0 + 2 \cdot 1 + 2 \cdot 1 = 0

乘开

3 \cdot 1 \cdot x + 3 \cdot 1 \cdot x : 6 x

6 x = 0

e x p an d f (x) (ln (x) - x^{2})^{3}

s im pl i f y (\frac{1}{x} \circ 7 - x) (x)

e x p an d \frac{5}{( x + 1 ) ^{2}}

e x p an d - 2 cos (2 (x - \frac{π}{4})) - 3

e x p an d r^{5^{^{'}}} (3 r^{5} + 4)