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受欢迎的代数 >

solvefor x,x^2-kx+64=0

解答

x, x^{2} - k x + 64 = 0

解答

x = \frac{k + k ^{2} - 256}{2}, x = \frac{k - k ^{2} - 256}{2}

求解步骤

x^{2} - k x + 64 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - k ) \pm ( - k ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

化简

(- k)^{2} - 4 \cdot 1 \cdot 64 : k^{2} - 256

x_{1, 2} = \frac{- ( - k ) \pm k ^{2} - 256}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - k ) + k ^{2} - 256}{2 \cdot 1}, x_{2} = \frac{- ( - k ) - k ^{2} - 256}{2 \cdot 1}

x = \frac{- ( - k ) + k ^{2} - 256}{2 \cdot 1} : \frac{k + k ^{2} - 256}{2}

x = \frac{- ( - k ) - k ^{2} - 256}{2 \cdot 1} : \frac{k - k ^{2} - 256}{2}

二次方程组的解是:

x = \frac{k + k ^{2} - 256}{2}, x = \frac{k - k ^{2} - 256}{2}

作图

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