4t^2-24t=0

解

4 t^{2} - 24 t = 0

t = 6, t = 0

解答ステップ

4 t^{2} - 24 t = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 24)^{2} - 4 \cdot 4 \cdot 0 = 24

t_{1, 2} = \frac{- ( - 24 ) \pm 24}{2 \cdot 4}

解を分離する

t_{1} = \frac{- ( - 24 ) + 24}{2 \cdot 4}, t_{2} = \frac{- ( - 24 ) - 24}{2 \cdot 4}

t = \frac{- ( - 24 ) + 24}{2 \cdot 4} : 6

t = \frac{- ( - 24 ) - 24}{2 \cdot 4} : 0

二次equationの解:

t = 6, t = 0